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John is 4 years older than David and Joe is 2 years younger than David. If the sum of their ages is 41, how old will John be in 8 years ' time?
  1. 24
  2. 25
  3. 17
  4. None of these
Explanation

Let's define the ages of the three people:

  • Let David's age be
    D    .
  • John's age is 4 years more than David's, so John's age is .
  • Joe's age is 2 years less than David's, so Joe's age is.

The sum of their ages is given as 41:

  1. Simplify the equation:


    D + D + 4 + D - 2 = 41
    3D + 2 = 41

  2. Subtract 2 from both sides:


    3D = 39

  3. Divide both sides by 3:


    D = 13

So, David is 13 years old.

  • John's age is D+4=13+4=17D + 4 = 13 + 4 = 17 years.
  • In 8 years, John's age will be:
    17 + 8 = 25 text{ years}

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